Question

Z=y(z-y)/x make the z as subject

Answer 1

Answer:

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Answer 2

Answer:

$here \: is \: your \: aswer$

Step-by-step explanation:

xz = yz-y^2

xz = yz-y^2xz-yz = -y^2

xz = yz-y^2xz-yz = -y^2z(x-y) = -y^2

xz = yz-y^2xz-yz = -y^2z(x-y) = -y^2z = -y^2/(x-y)

xz = yz-y^2xz-yz = -y^2z(x-y) = -y^2z = -y^2/(x-y)============

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