z1=2+3i z2=1+2i then find z1.z2-z1³
Answers
Answered by
2
Step-by-step explanation:
z1.z2-z1³
=(2+3i)(1+2i)-(2+3i)³
=(2+4i+3i-6)-(8+36i-54-27i)
=(-2+7i)-(-48+9i)
=-2+7i+48-9i
=46-2i
Answered by
0
Answer:
38-2i
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thanq.
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