Question

z1=2+3i z2=1+2i then find z1.z2-z1³​

Answer 1

Step-by-step explanation:

z1.z2-z1³

=(2+3i)(1+2i)-(2+3i)³

=(2+4i+3i-6)-(8+36i-54-27i)

=(-2+7i)-(-48+9i)

=-2+7i+48-9i

=46-2i

Answer 2

Answer:

38-2i

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thanq.