Question

Z1= 2+8i Z2 = 3-4i find Z1* Z2 AND Z1/Z2????? AND ALSO REPRESENT IN a+ib form

Answer 1

Answer:

Z1×Z2 = 40 + 4i

Z1/Z2 = - 26/25 + 32i/25

Step-by-step explanation:

Z1 = 2 +8i

Z2 = 3 - 4i

Z1 ×Z2 = (2 + 8i) (3 - 4i) = 6 -8i + 12i - 32i^2

= 6 + 4i + 32. because of i^2 = -1

= 40 + 4i

a=40 and b= 4

Z1/ Z2 = (2+ 8i) / (3 - 4i)

= [(2+ 8i) / (3 - 4i)] × [(3+4i) / (3 + 4i)]

= (6 + 8i + 24i + 32i^2) / (9 - 16i^2)

= (6 + 32i -32)/ (9 +16) we know i^2 = -1

=(- 26 + 32i) / 25 = ( - 26/25 + 32i/25)

a = - 26/25 and b= 32/25