|z1|=2,|z2|=3,|Z3|=4 and |2z1+3z2+4z3|=9 then |8z2z3+27z3z1+64z1z2|=?
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assuming all are positive
2z1+3z2+4z3= 4+9+16
to get answer 9 z2 has to be negative so z2=-3
so final and = 8*-3*4+27*4*2+64*2*-3= -264
2z1+3z2+4z3= 4+9+16
to get answer 9 z2 has to be negative so z2=-3
so final and = 8*-3*4+27*4*2+64*2*-3= -264
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Answer:
question is wrong. it's not 9, is 4
I am also looking for this question. it is in complex numbers
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