Question

Z1=(-9+5i) Z2 (4-6i)
find Z1*Z2​

Answer 1

Given :-

$z_1 = (-9+5i)$

$z_2 = (4 - 6i)$

To find :-

Product of the given complex numbers

Solution :-

${ \implies z_1\times z_2 = (-9+5i) (4-6i)}$

${ \implies z_1\times z_2 = -9(4 - 6i)+5i (4-6i)}$

${ \implies z_1\times z_2 = -36 + 54i + 20i - 30 {i}^{2} }$

${ \implies z_1\times z_2 = -36 + 54i + 20i - 30 ( - 1) }$

${ \implies z_1\times z_2 = -36 + 74i + 30 }$

${ \implies \underline{ \underline{ z_1\times z_2 = -6 + 74i }}}$

Hence the product of the given complex numbers is $-6+74i$.

Remember that,

• $i = \sqrt{-1}$
• $i^2 = -1$
• $i^3 = -i$
• $i^4 = 1$