Z1 and z2 are two complex numbers such that z1-2z2/2-z1z2 is unimodular
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Answer:
Step-by-step explanation:
if z unimodular then |z|=1 also use property of moduls i.e zz`=|z|^2
given z^2 is not unimodula |z|2≠1
and z1-2z2/2-z1z2 is unimodular
z1-2z2/2-z1z2 =1
⇒ |z1-2z2|^2=|2-z1z2`|^2
⇒(Z1-2Z2)(Z1`-2Z2` )=(2-Z1Z2` )(2-Z1`Z2)
∵ZZ`=|z|^
⇒|Z2|^2+4|Z2|^2-2Z1`Z2-2Z1Z2`
⇒(|Z1|^2-1)(|Z1|-4)=0
|Z2|≠1
|zZ|=2
Z1=X+iy
X^2+Y^2=(2)^2
z1 lies on redius is 2
hope it is helpful
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