|z¹+z²|=|z¹|+|z²| is possible if
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2
Answer:
To prove,
∣z
1
+z
2
∣=∣z
1
∣+∣z
2
∣
taking squares
∣z
1
∣
2
+∣z
2
∣
2
+2∣z
1
∣∣z
2
∣cos(argz
1
−argz
2
)
=∣z
1
∣
2
+∣z
2
∣
2
+2∣z
1
∣∣z
2
∣
hence cos(argz
1
−argz
2
)=1
arg(z
1
−argz
2
)=0
⇒arg(z
1
)=arg(z
2
)
Answered by
1
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