Question

z²+19z-150
answer this fast​

Answer 1

Given equation,

z^{2} + 19z-150=0z

2

+19z−150=0

Solving, we get,

$$\begin{lgathered}z^{2} +19z-150=0\\=> z^{2} +25z-6z-150=0\\=>z(z+25)-6(z+25)=0\\=>(z-6)(z+25)=0\end{lgathered}$$

$$\boxed{\boxed{\bold{Therefore, \ the\ factors \ are \ (z-6) \ and \ (z+25).}}}$$

Answer 2

Step-by-step explanation:

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