z2-4
dz evaluated anticlockwise around the circle 1z - il = 2, is -
z2+4
(a)
–41
(b) 0
(c) 2 +
(d) 2-0
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Answer:
2+4=6
a)2+4-41=-35
b)2+4+0=6
c)2+4+2=8
d)2+4+2-0=8
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