Question

z2-z+ 1/4=0 using quadratic equations

Answer 1

${z}^{2} - z + \frac{1}{4} \\ {(z)}^{2} - 2.(z). \frac{1}{2} + {( \frac{1}{2} )}^{2} \\ {(z - \frac{1}{2}) }^{2} \\ (z - \frac{1}{2} )(z - \frac{1}{2} ) \\ hope \: this \: helps \: you$

Answer 2

z²-z+(1/4)=0
Multiply all through by 4
4z²-4z+1=0
4z²-2z-2z+1=0
2z(2z-1)-1(2z-1)=0
(2z-1)²=0
Therefore, z=1/2 twice