Question

z4-z3+3z2-2z+2÷z2+2​

Answer 1

Answer:

($z^{2}-z+1$)

Step-by-step explanation:

We have to calculate the value of $\frac{(z^{4}-z^{3} +3z^{2}-2z+2  )}{z^{2}+2 }$.

Now, to calculate the above value, first try to factorize the expression

$(z^{4}-z^{3} +3z^{2}-2z+2  )$

=$z^{4}+2z^{2}-z^{3} -2z+z^{2} +2$

=$z^{2} (z^{2}+2 )-z(z^{2}+2 )+(z^{2}+2)$

=$(z^{2}+2)(z^{2} -z+1)$

Hence,  $\frac{(z^{4}-z^{3} +3z^{2}-2z+2  )}{z^{2}+2 }$.

=($z^{2}-z+1$) (Answer).

[Note: If you have to divide an algebric equation of any degree with another algebric equation of any degree, try to factorize the first expression with one factor as the second expression.]

Answer 2

Answer:

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