Question

ZA+ZB = 90° 2661, 621 (1, 1+
tan A
tan B
= secA​

Answer 1

Step-by-step explanation:

√(tanA tan B + tan A cot B)/(sinA secB)

∵ tanB = cot(90-B); cotB = tan(90-B); secB = cosec(90-B) & 90-B=A

∴√(tanA cotA + tan A tanA)/(sinA cosecA) 

=√(1+tan²A)/1

=√sec²A/1

=secA/1 = secA .................. Hence Proved

HOPE IT HELPS................... :)

Answer 2

Answer:

1=1

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