ZA+ZB = 90° 2661, 621 (1, 1+
tan A
tan B
= secA
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Step-by-step explanation:
√(tanA tan B + tan A cot B)/(sinA secB)
∵ tanB = cot(90-B); cotB = tan(90-B); secB = cosec(90-B) & 90-B=A
∴√(tanA cotA + tan A tanA)/(sinA cosecA)
=√(1+tan²A)/1
=√sec²A/1
=secA/1 = secA .................. Hence Proved
HOPE IT HELPS................... :)
Answered by
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Answer:
1=1
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