Question

Zahid had invested in a bank scheme which of interested 8.6 % annual for 7.8 year how much interest will be invested for 20000 rupees

Answer 1

Given:-

•Rate of interest=8.6%

•Time is given=7.8years

•Principal = 20000rupees

To Find:-

•How much interest will be invested

Solution:-

we have,

• Principal=20000rupees
• Rate=8.6%
• Time=7.8years

Using Formula:

$\: \: \sf \: simple \: interest = \frac{principal \times rate \times time}{100}$

Now substitue the values,

$\: \: \sf \: s.i = \frac{20000 \times 86 \times 78}{100 \times 10 \times 10} \\ \\ \: \: \sf \: s.i = 2 \times 86 \times 78 \\ \\ \: \: \sf \: s.i = 13416 \: rupees$

Henceforth,Simple Interest is 13416 rupees.

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Extra Info...

•Principal=Simple Interest *100/Rate*time

•Time=Simple Interest*100/Principal*rate

•Rate=Simple Interest*100/Principal*time

•Amount=Principal+Simple Interest

•Principal=Amount-Simple Interest

•Simple Interest=Amount-Principal