Question

Zalika uses the formula v2 = u2 + 2as. When she substitutes v = 4, u = 3 and a = 7 into the formula she gets the equation 8 = 6 + 14s. Is Zalika correct? Show how you worked out your answer.

Answer 1

Answer:

No Zalika is not correct

Because -

When you substitute v square - (  Final Velocity ) as 4 square = 16

When you substitute u square  - ( Initial Velocity ) as 3 square = 9

When you substitute a - ( Acceleration ) as 7

2as = 2 * 7 * s = 14 * s = 14s

Now let us consider the given equation as LHS

LHS -

8 = 6 + 14s

Now let us consider the obtained equation as RHS

RHS -

16 = 9 + 14s

Consider LHS = RHS

Where LHS -

0 = 6 + 14s - 8

= 14s - 2

Where RHS -

0= 9 + 14s - 16

= 14s - 7

Now we get an equation -

14s - 2  = 14s - 7

-2  + 7 =14s - 14s

5 ≠ 0

Hence LHS is not equal to RHS .

So , The given equation and the obtained equation is not equal.

Zalika is not correct !

I hope it is correct .