Physics, asked by NPERDUESTU, 1 month ago

Zena was originally traveling 40 mi/hr and then began accelerating at a speed of 60 mi/ hr^2 for 0.25 hours. What was her final speed? 0.0125

Answers

Answered by Yuseong
5

Anѕwєr :

55 mi/hr

Explαnαtion :

As per the provided information in the given question, we have :

  • Initial velocity (u) = 40 mi/hr
  • Acceleration (a) = 60 mi/hr²
  • Time (t) = 0.25 hours

We've been asked to calculate her final velocity (v).

By using the First Equation Of Motion :

★ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time

Substitute the values in the formula.

→ v = 40 + 60(0.25)

→ v = 40 + 15

v = 55 mi/hr⠀⠀⠀⠀⠀⠀⠀[Answer]

Therefore, the final speed of her is 55 mi/hr.

\rule{200}2

Leαrn Morє :

Equations of motion :

⠀⠀⠀⠀⠀⠀⠀★ v = u + at

⠀⠀⠀⠀⠀⠀⠀★ s = ut + ½at²

⠀⠀⠀⠀⠀⠀⠀★ v² – u² = 2as

Where,

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • s denotes distance
  • t denotes time

\rule{200}2

Answered by midhuna49
0

Answer:

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