Question

zero is the centre of a circle of radius 5cm op pendicular to a b and p pendicular to c d a b c d a b is equal to 6 cm equal to 8 cm diameter PQ​

Answer 1

Answer:

GOOD MORNING HAVE A FANTASTIC DAY

Answer 2

Answer:

PQ= 7cm

Step-by-step explanation:

ince the perpendicular from the center of the circle to a chord bisects the chord.

P and Q are the mid points of AB and CD

In right triangles OAP and OCQ, we have

OA^2 = OP^2 + AP^2 and OC^2 = OQ^2 + CQ^2

5^2 = OP^2 + 32 and 52 = OQ^2 + 4^2

OP^2 = 5^2 - 3^2 and  OQ^2 = 5^2 - 4^2

OP^2 = 16 and OQ^2 = 9

OP = 4 and  OQ = 3

PQ = OP + OQ = 4 + 3 = 7 cm