Question

Zero of p(x) =x^2-2x-3 are​

Answer 1

3.-1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

The zeros of the polynomial

$\: \: \: x^2 - 2x - 3 \\ </p><p></p><p>∴ (x-3) (x+1) = 0 \\ </p><p></p><p>⇒x = 3 \\ </p><p></p><p></p><p> or \: x =-1.$