Question

zero of polynomial P (x)x^2+x-6?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

p(x)=x²+x-6

Step-by-step explanation:

p(x)=x²+x-6

So, in order to find the zeroes of the polynomial we have to equate the polynomial with 0.

i.e. x²+x-6=0

x²-2x+3x-6=0

x(x-2)+3(x-2)=0

(x-2)(x+3)=0

By equating both the factor (x-2) and (X+3) to 0, we get x-2=0

x=2 and x+3=0

x=-3

Hence the zeroes of the polynomial are 2 and -3.