zero of the polynomial 3x square + 4 root 3 X + 4
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3x^2 + 4√3x + 4
=(√3x)^2 + 2×2×√3 + (2)^2
=(√3x + 2)^2
Therefore zeros of the polynomial are : -2÷√3
=(√3x)^2 + 2×2×√3 + (2)^2
=(√3x + 2)^2
Therefore zeros of the polynomial are : -2÷√3
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Answer:
3x²+4√3x+4
=3x²+2√3x+2√3x+4
=√3x(√3x+2)+2(√3x+2)
=(√3x+2)(√3x+2)
=>x=-2/√3,-2/√3
=>x=-2√3/3, -2√3/3 (rationalise)
Zeros= -2√3/3, -2√3/3
Hope it helps u.....^_^
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