Question

zero of the polynomial m²y²-1 is​

Answer 1

${\huge{\underline{\underline{\sf{Answer\checkmark}}}}}$

$\rm \: the \: zero \: of \: the \: polynomial \:$

$\rm \: {m}^{2} {y}^{2} - 1 = 0 \\ \\ \implies \: \rm \: {m}^{2} {y}^{2} = 1 \\ \\ \rm \implies \: {y}^{2} = \frac{1}{ {m}^{2} } \\ \\ \implies \: \rm \: y = ± \frac{1}{m}$

so, it is the zero of the Polynomial

Answer 2

${\huge{\underline{\underline{\rm{Answer\checkmark}}}}}$

$\mapsto \: \rm \: {m}^{2} {y}^{2} - 1 = 0$

$\mapsto \: \rm \: {m}^{2} {y}^{2} = 1$

$\mapsto \: \rm \: {y}^{2} = \dfrac{1}{ {m}^{2} }$

$\mapsto \: \rm \: y = ± \frac{1}{m}$

These are the zeroes