Question

zero of the polynomial x²+1(x=r) is ​

Answer 1

$\huge\bf\underline \red{\underline{Answer}}$

Rewrite the polynomial x

2 −1=0 as:

x 2−1=0

⇒x 2−1 2=0

⇒(x−1)(x+1)=0(∵a 2

−b 2

=(a−b)(a+b))

⇒(x−1)=0,(x+1)=0

⇒x=1,x=−1

Hence, the zeroes of the polynomial x

2−1 are 1,−1.

hopes its helps you..

Answer 2

Rewrite the polynomial x

2

−1=0 as:

x

2

−1=0

⇒x

2

−1

2

=0

⇒(x−1)(x+1)=0(∵a

2

−b

2

=(a−b)(a+b))

⇒(x−1)=0,(x+1)=0

⇒x=1,x=−1

Hence, the zeroes of the polynomial x

2

−1 are 1,−1.

hope it helps you ✌️✅✅✅