Question

Zero polynomial 4 z plus 3

Answer 1

Answer:

1 Answer +1 vote answered Aug 14, 2020 by Dev01 (51.8k points) selected Aug 14, 2020 by Sima02   Zero of the polynomial, g1(z) = 0 z-3 = 0 z = 3 Therefore, zero of g(z) = – 2a Let p(z) = az3 + 4z2 + 3z - 4 So, substituting the value of z = 3 in p(z), we get, p(3) = a(3)3 + 4(3)2 + 3(3) - 4 ⇒p(3) = 27a+36+9-4 ⇒p(3) = 27a+41 Let h(z) = z3 - 4z + a So, substituting the value of z = 3 in h(z), we get, h(3) = (3)3 - 4(3) + a ⇒h(3) = 27-12+a ⇒h(3) = 15+a

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