Math, asked by kbadrish81, 9 months ago

Zeroes of a polynomial p(x) = 6x² - 24 is

Answers

Answered by szyfrowac
1

Step-by-step explanation:

6x^{2}-24\\=6(x^{2}-4)\\=6(x-2)(x+2)\\\\

hence the zeros are 2 and -2

Answered by harshitha6143
1

Answer:

6x^2-24=0

6x^2=24

x^2=24/6

x^2=4

x =root 4

x=2

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