Question

Zeroes of p(x) = x^2 - 27 = 0 are _______

please answer this fast ​

Answer 1

Answer:

±3√3

Step-by-step explanation:

Two roots of quadratic equation, so take plus and minus both

Answer 2

Answer:

Zeroes of p(x) = x² - 27 = 0 are +3√3 and -3√3.

Step-by-step explanation:

P(x)=x²-27

Now p(x)=0

=> x²-27 = 0

=> x² = 27

=> x = ±√27

= +3√3&-3√3

The zeroes are+3√3 and -3√3.