Question

Zeroes of p(x) = x2-27 are:

Answer 1

Answer:

Step-by-step explanation:

P(x)=x²-27

Now p(x)=0

=> x²-27=0

=> x²=27

=> x=±√27

=+3√3&-3√3

So the zeroes are+3√3 and -3√3.

Hope you got it.

Answer 2

Zeroes of p(x) = x² - 27 are - 3√3 , 3√3

Given : The polynomial p(x) = x² - 27

To find : Zeroes of the polynomial

Solution :

Step 1 of 2 :

Write down the given polynomial

The given polynomial is

p(x) = x² - 27

Step 2 of 2 :

Find the zeroes of the polynomial

Since degree of the polynomial = 2

So the polynomial has two zeroes

For Zeroes of the polynomial we have

p(x) = 0

$\displaystyle \sf{ \implies {x}^{2} - 27 = 0}$

$\displaystyle \sf{ \implies {x}^{2} = 27 }$

$\displaystyle \sf{ \implies x = \pm \: \sqrt{27} }$

$\displaystyle \sf{ \implies x = \pm \: \sqrt{ {3}^{2} \times 3} }$

$\displaystyle \sf{ \implies x = \pm \: 3\sqrt{ 3} }$

Zeroes of p(x) = x² - 27 are - 3√3 , 3√3

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