Zeroes of p(z) = z^2 - 27 are........
and.........
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Answer:
–√27,√27 these are zeroes of the equation...
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Step-by-step explanation:
z³-27=0
z³-3³=0
(z-3)(z²+3z+9)=0
z= 3 or z²+3z+9=0
z=3 or z= -3±3√3i
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