Math, asked by human62, 1 month ago

Zeroes of p(z) = z² – 27 are ______ and ______ .​

Answers

Answered by ashleshasarma4206
5

Answer:

ZEROES OF p(z) = z² - 27 are 3√3and -3√3

Step-by-step explanation:

To find zeroes of p(z), we take

p(z)=0

=> z² - 27=0

=> z² = 0+27

=> z² = 27

=> z = ±√27

=> z = ± 3√3

Therefore, zeroes of p(z) = z²-27 are 3√3 and -3√3

Answered by aryansinghghanata
0

Answer:

ZEROES OF p(z) = z² - 27 are 3√3and -3√3

Step-by-step explanation: To find zeroes of p(z), we take

p(z)=0

=> z² - 27=0

=> z² = 0+27

=> z² = 27

=> z = ±√27

=> z = ± 3√3

Therefore, zeroes of p(z) = z²-27 are 3√3 and -3√3

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