Question

zeroes of polynomial x^2+99x+127 are
2 points
Both positive
Both negative
One positive one negative
Both equal ​

Answer 1

Answer:

use the discriminant to find nature of roots or zeroes

∆=b^2-4ac

where b is x coefficient,a is x^2 coefficient and c is constant .

∆=(99)^2-4*1*127

∆=9801-508

∆=9293

so, discriminant is >0 ,so zeroes are real and different .

So, answer is both positive