Question

Zeroes of polynomial x cube +6x square +11x+6

Answer 1

${x}^{3} + 6 {x}^{2} + 11x + 6 \\ let \: x = - 1 \\ x + 1 = 0 \\ on \: dividing \: the \: cubic \: polynomial \: by \: x + 1 \\ we \: get \: {x}^{2} + 5x + 6 \: as \: quotient \\ spliting \: the \: middle \: term \: we \: get \: zeros \: as \: \\ - 2 \: and \: - 3 \\ therefore \: zeros \: are \: - 1 \: - 2 \: - 3$