Question

zeroes of the following polynomial x^2 - 3x +2 is







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Answer 1

Answer:

=>x²-x-2x+2=0

=>x(x-1)-2(x-1)=0

=>(x-1)(x-2)=0

=>roots are 1,2

Answer 2

p(x) = x² - 3x + 2

= x² - x(2+1) + 2

= x²-2x-x+2

= x(x-2)-1(x-2)

= (x-2) (x-1)

now , x-2 = 0

=> x = 2

and x-1 = 0

=> x = 1

The zeroes of p(x) are 2 and 1.

we know that,

sum of zeroes = 2+1 = 3 = coefficient of x/coefficient of x²

product of zeroes = 2×1 = 2 = constant/coefficient of x² .