Question

zeroes of the polynomial 2x^2-18 are​

Answer 1

Answer:

$2 {x}^{2} - 18 = 0 \\ \\ 2 {x}^{2} = 18 \\ \\ {x}^{2} = \frac{18}{2} \\ \\ {x }^{2} = 9 \\ \\ x = \sqrt{9} \\ \\ x = ±3$

So the roots are - 3 and + 3.

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Answer 2

Answer:

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Step-by-step explanation:

x=3