Question

zeroes of the polynomial 3x2+11x+0​

Answer 1

Answer:

3x^2+11x=0

=>x(3x+11)=0

Either,

x=0 or 3x+11=0

=>x= -11/3

Answer 2

$\huge{\boxed{\fcolorbox{cyan}{pink}{answer}}}$

$p(x)= {2x}^{3} + {3x}^{2} −11x−6</p><p></p><p>$

Since x=−3 is a zero of p(x)

So, by factor theorem x+3 is a factor of p(x)

$quotient \: is  {2x}^{2} −3x−2 and \: remainder \: is  \: 0.$

Therefore,

${2x}^{3} + {3x}^{2} −11x=(x+3)( {2x}^{2} −3x−2)$

=(x+3)(2x+1)(x−2)

for other zeroes of p(x)

2x+1=0,x−2=0

$Hence \: the \: other \: zeroes \: are  - \frac{1}{2} ,2$

hope this help you...

-3idiots29