Question

Zeroes of the polynomial p(x) 2x2-9-3x

Answer 1

here is ur answer mate hope it helps you

Answer 2

Answer:

Zeros are 3 and (- 3/2)

Step-by-step explanation:

2x² - 3x - 9 = 2(x² - $\frac{3}{2}$x - $\frac{9}{2}$) = 2[(x² - 2×$\frac{3}{4}$x + $\frac{9}{16}$) -

2[(x - $\frac{3}{4}$)² - $\frac{81}{16}$] = 2(x -

$x_{1}$ = 3

$x_{2}$ = - $\frac{3}{2}$