Question

zeroes of the polynomial p(x)=4x^2-12x-9

Answer 1

4x²-12x-9 = 0
4x²-6x-6x-9 = 0
2x(2x-3)-3(2x-3)=0
(2x-3)(2x-3)=0
(2x-3)²=0
2x-3=0
2x=3
x=3/2 

Answer 2

Answer:

P(x)= 4x² - 12x + 9

4x²- 12x + 9 = 0

4x²- 6x - 6x +9 = 0

2x(2x - 3) - 3(2x - 3) = 0

(2x - 3) (2x - 3)

x = 3/2    x = 3/2

x = 3/2 ; 3/2 are the zeros of the given polynomial.

Step-by-step explanation: