Question

zeroes
of the polynomial P(x)= x² - 9
are​

Answer 1

Step-by-step explanation:

hope it is helpful to you

Answer 2

Answer:

${x}^{2} - 9 = 0$

${(x)}^{2} - {(3)}^{2} = 0$

$(x + 3)(x - 3) = 0$

$(x + 3) = 0 \: and \: (x - 3) = 0$

$x = - 3 \: and \: x = 3$

3 and -3 are the zeros of the polynomial.

Ans. 3 and -3

Hope it helps.