Question

zeroes of the polynomial P(y)=9y^2-49 are​

Answer 1

Answer:

9y²-49 = (3y)²-(7)²

= (3y+7) (3y-7)

3y+7=0 , 3y-7=0

y= -7/3 y = 7/3

zeroes are -7/3 , 7/3

hope it will help you

Answer 2

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