Question

Zeroes of the polynomial x² - 2 x -8 are *​

Answer 1

Answer:

Ur answer

${x}^{2} - 2x - 8 \\ = {x}^{2} - 4x + 2x - 8 \\ = x(x - 4) + 2(x - 4) \\ = (x + 2)(x - 4)$

Zeroes of the Polynomial are

(-2) and (4).

Step-by-step explanation:

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Answer 2

Answer:

here's your answer

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