Zeroes of the polynomial-x3(x cube)
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![- {x}^{3} \\ \\ \\ Let \: x \: be \: zero \\ \\ \\ - {0}^{3} \\ \\ \\ x = 0 - {x}^{3} \\ \\ \\ Let \: x \: be \: zero \\ \\ \\ - {0}^{3} \\ \\ \\ x = 0](https://tex.z-dn.net/?f=-+%7Bx%7D%5E%7B3%7D+%5C%5C+%5C%5C+%5C%5C+Let+%5C%3A+x+%5C%3A+be+%5C%3A+zero+%5C%5C+%5C%5C+%5C%5C+-+%7B0%7D%5E%7B3%7D+%5C%5C+%5C%5C+%5C%5C+x+%3D+0)
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CaptainKhan:
Hi kudi
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0
P(x) = x^3
Let k be a zero of the poly.
Then. P(k)= 0
=> k^3 = 0
=> k= cube root 0
=> k = 0
Hence, zeroes are 0, 0 and 0.
Let k be a zero of the poly.
Then. P(k)= 0
=> k^3 = 0
=> k= cube root 0
=> k = 0
Hence, zeroes are 0, 0 and 0.
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