zeroes of the quadratic polynomial x square + 7x + 12 are .
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Answered by
2
Given polynomial x²+7x+12
x²+4x+3x+12
x(x+4)+3(x+4)
(x+3)(x+4)
-3,-4 are the zeros
sum of zeros=-7=-b/a=-7
product of zeros =12=c/a=12
hence verified.
Hope it helps!
Answered by
0
Answer:
x²+7x+12
Step-by-step explanation:
x²+4x+3x+12
x²+4x-3(x+4)
x(x+4)×-3(x+4)
x+4,x-3
x=-4
x=3
sum of zeros lf+b
-4+3=-1/12
product of zero
-4×3=-12=-12/1
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