Question

zeroes of x2 -2x -3 are
1 point
3,1
3,-1
-3,-1​

Answer 1

Answer:

answer is 3 &-1

Step-by-step explanation:

• x^2-3x+x-3. x(x-3)+1(x-3). (x+1)(x-3)

Answer 2

Step-by-step explanation:

${x}^{2} - 2x - 3 = 0 \\ = > {x}^{2} - 3x + x - 3 = 0 \\ = > x(x - 3) + 1(x- 3) = 0 \\ = > (x + 1)(x - 3) = 0 \\ x = - 1 \\ x = 3 \\ x > - 1 \: and \: 3$