zeroes of x2 - 5x - 6 ( factors)
Answers
Answer:
(x-2) (x-3)
Explanation:
hope this is right answer
Answer:
x = - 3, - 2
Step-by-step explanation:
Given : f(x) = x² + 5x + 6
On comparing this with ax² + bx + c, we get
a = 1, b = 5, c = 6
Using Middle Term Factorisation, we get
→ x² + 2x + 3x + 6
Taking out common terms, we get
→ x(x + 2) + 3(x + 2)
→ (x + 3)(x + 2)
To find the zeroes, these factors should be equal to zero.
Using zero product rule.
→ (x + 3) = 0 and (x + 2) = 0
→ x = - 3 and x = - 2
In Middle Term Factorisation, we factorise the middle term only.
First we multiply 'a' and 'c'.
Then we have to find such a pair of number such that on addition or subtraction, the result equals to 'b' and on multiplication, the result equals to the multiplication of 'a' and 'c'.
We get the two terms : 2 and 3
Addition = (2) + (3) = 5 = b
Multiplication = (2)(3) = 6 = Product of 'a' and 'c' i.e. (1)(6) = 6
Explanation:
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