zeroesnof f(x)=x²-8 are
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Hi ,
f( x ) = x² - 8
To find zeroes of f( x ) , we have to take
f( x ) = 0
x² - 8 = 0
x² = 8
x = ± √8
x = ± 2√2
Therefore ,
2√2 , - 2√2 are two zeroes of f( x ).
Option ( B ) is correct.
I hope this helps you.
: )
f( x ) = x² - 8
To find zeroes of f( x ) , we have to take
f( x ) = 0
x² - 8 = 0
x² = 8
x = ± √8
x = ± 2√2
Therefore ,
2√2 , - 2√2 are two zeroes of f( x ).
Option ( B ) is correct.
I hope this helps you.
: )
Answered by
4
Hi friend!!
Given f(x)=x²-8
=(x+2√2)(x-2√2)
zeros of the polynomial are the values for which the given polynomial is equal to zero.
Therefore -2√2,2√2 are the zeros of the polynomial.
(b) is the correct option.
I hope this will help u ;)
Given f(x)=x²-8
=(x+2√2)(x-2√2)
zeros of the polynomial are the values for which the given polynomial is equal to zero.
Therefore -2√2,2√2 are the zeros of the polynomial.
(b) is the correct option.
I hope this will help u ;)
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