Question

Zeros of a f( x) = 6 x ²– 4 x – 2

Answer 1

$x = 6 {x}^{2} - 4x - 2 \\ \\ 3 {x}^{2} - 2x - 1 \\ \\ 3 {x}^{2} - 3x + x - 1 \\ \\ 3x(x - 1) + 1(x - 1) \\ \\ 3x + 1 \: andx - 1 \\ \\ x = 1$

Answer 2

Answer:

f(x) = 6x²-4x-2

=> 6x²-6x+2x-2... * {6 ×(-2)} = -12*

=> (6x²-6x)+(2x-2).... *-6x+2x = -4x*

=> 6x(x-1)+2(x-1)

=> (6x+2)(x-1)

=> x = -2/6 , x = 1

=> x = -1/3 , x = 1

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