Zeros of P of x is equal to x square - 2 x minus 3 option G 3 and 1 option b 3 and -1 option C - 3 and -1 d 1 and -3
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P(x) = x^2 -2x -3
P(0) = x(0) -2(0) -3
P(0) = 0 -0 -3
P(0) = -3
IF CAN'T FIND THE 1 FROM THE OPTION
AND THERE IS ONLY ONE OPTION
WHICH CONTENT -3 AND 1 SO I
PROBABLY GO WITH OPTION D.
(D) 1 and -3
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