Question

Zeros of p(x)=x^2 -2x-3 are

Answer 1

Answer:

= x^2 -3x +x-3=0

= x (x-3)+1 (x-3)=0

= (x+1)(x-3)=0

= x+1=0

x=-1

= x-3 =0

x=3

so the require zeros of p (x) = -1 and 3

Answer 2

here's Ur answer

• let X = 0

p(0)= 0^2-2×0-3

=0-0-3

=-3

• let X =1

p(1)=1^2-2×1-3

=1-2-3

=1-5

=-4

• let X=2

p(2)=2^2-2×2-3

=4-4-3

=-3

• let X=3

p(3)=3^2-2×3-3

=9-6-3

=9-9

=0

1. hence x=3 is the zero of p(X)

hope it helps u

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