Question

zeros of p(x) =x to the power 2 -2x -3are

Answer 1

3,-1 are the answers for this question

Answer 2

Hey there!!
$p(x) = {x}^{2} - 2x - 3 = 0 \\ = > {x}^{2} - 3x + x - 3 = 0 \\ = > ( {x}^{2} - 3x) + (x - 3) = 0 \\ = > x(x - 3) + 1(x - 3) = 0 \\ = > (x + 1)(x - 3) = 0\\ = > x = - 1or3$
Hope this helps u!!