zeros of p(z) = Z square - 27 are ____and ____.
Answers
Answered by
65
Let p(z) = z^2 - 27
For zeros of the polynomial:
p(z) = 0
z^2 - 27 = 0
z^2 = 27
z = ±√27
z = ±3√3
Hence, zeros of p(z) = Z^2 - 27 are +3√3 and -3√3.
Answered by
2
Step-by-step explanation:
hope this will help you
plz mark me as brainlist
Attachments:

Similar questions