Math, asked by abhishekrajput6916, 1 year ago

Zeros of polynomial x²+4x+8 is​

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Answers

Answered by mysticd
1

Solution :

Compare x² + 4x + 8 with

ax² + bx + c , we get

a = 1 , b = 4 , c = 8

Sum of the zeroes = -b/a

= -4/1

= -4

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