zeros of polynomials
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sum of zeroes of the polynomial are -b/a
-(-6)/1
=6.
:-)hope it helps u.
pls mark as brainliest.
-(-6)/1
=6.
:-)hope it helps u.
pls mark as brainliest.
Answered by
4
In general, In a quadratic equation like, ax² + bx +c = 0, The sum of zeroes of is -b/a,
The given Polynomial ,
x² - 6x + 7,
So by the statement, The sum of zeroes of this Polynomial is -(-6)/1 = 6,
Another method,
First, Let us find zeroes of polynomial and find the sum,
Zeroes of the polynomial is (-b+√(b²-4ac))/2a and, (-b-√b²-4ac)2a,
Add them, We get -(b-b)/2a,
=> -2b/2a
=> -b/a again,
So therefore the sum of zeroes of the given polynomial is 6,
Hope you understand, Have a great day !
Thanking you, bunti 360 !
The given Polynomial ,
x² - 6x + 7,
So by the statement, The sum of zeroes of this Polynomial is -(-6)/1 = 6,
Another method,
First, Let us find zeroes of polynomial and find the sum,
Zeroes of the polynomial is (-b+√(b²-4ac))/2a and, (-b-√b²-4ac)2a,
Add them, We get -(b-b)/2a,
=> -2b/2a
=> -b/a again,
So therefore the sum of zeroes of the given polynomial is 6,
Hope you understand, Have a great day !
Thanking you, bunti 360 !
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