Question

zeros of quadratic polynomial and verify the Relationship between the zeros and the co efficient of
$x { }^{2} - 5x$
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Answer 1

$x^2-5x=0\\\\\x(x-5)=0\\\\x=0\\\\and \\\\x =5$

In this equation a = 1 , b = -5 and c = 0 .

Relation :

1 ) -b / a = sum of zeroes

- (-5) / 1 = 5 + 0

5 = 5

2) c / a = product of zeroes

0 / 1 = 5 × 0

0 = 0

Answer 2

Answer:

given f(x) = x² - 5x

to find zeros of the given polynomial

and verify the relationship between zeros and coefficients

f(x) = x² - 5x = 0

=> x(x - 5) = 0

=> x =0 and x = 5 are the zeros

now we can write the given polynomial in the standard form ax²+bx+c = 0, as

1x² + (-5)x + 0 = 0

a = 1, b = -5 and c = 0

relation between the zero and coefficients is,

-b/a = sum of zeros and. c/a = product of zeros

sum of zeros = 0 + 5 = 5, -b/a = -(--5)/1 = 5

product of zeros = 0 × 5 = 0, c/a = 0/1 = 0

verified the relationship